Reverse number rhombus pattern program in Java



import java.util.Scanner;
public class ReverseRhombus
{
 public static void main(String[] args) 
 {
  int num;
  Scanner sc = new Scanner(System.in);
  System.out.print("Enter number of rows : ");
  num = sc.nextInt();
  for (int r = 1; r <= num; r++) {
   for (int sp = num - r; sp >= 1; sp--) {
    System.out.print(" ");
   }
   for (int c = r; c >= 1; c--) {
    System.out.print(c);
   }
   for (int c = 2; c <= r; c++) {
    System.out.print(c);
   }
   System.out.println();
  }
  for (int r = 1; r <= num; r++) {
   for (int sp = r; sp >= 1; sp--) {
    System.out.print(" ");
   }
   for (int c = num - r; c >= 1; c--) {
    System.out.print(c);
   }
   for (int c = 2; c <= num - r; c++) {
    System.out.print(c);
   }
   System.out.println();
  }
 }
}

Output:


Enter number of rows : 5


        1

      212
    32123
  4321234
543212345
  4321234
    32123
      212
        1
     

BUILD SUCCESSFUL (total time: 3 seconds)



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