### Java program to find out the sum of A.P. series

Arithmetic progression (A.P.):
A series of numbers in which difference of any two consecutive numbers is always a same number that is constant. This constant is called as common difference.

Example of A.P. series:
3 + 8 + 13 + 18 + 23 + 28 + 33

package demo;
import java.util.Scanner;
public class Series {
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
int a, d, n, tn;
int sum = 0;

System.out.print("Enter the first number of the A.P. series: ");
a = sc.nextInt();

System.out.print("Enter the total numbers in the A.P. series: ");
n = sc.nextInt();

System.out.print("Enter the common difference of A.P. series: ");
d = sc.nextInt();

sum = (n * (2 * a + (n - 1) * d)) / 2;
tn = a + (n - 1) * d;
System.out.print("Sum of the series A.P.: ");

for (int i = a; i <= tn; i = i + d)
{
if (i != tn)
{
System.out.print(i + " + ");
} else
{
System.out.print(i + " = " + sum + " ");
}
}
}
}

Output:

Enter the first number of the A.P. series: 3
Enter the total numbers in the A.P. series: 7
Enter the common difference of A.P. series: 5
Sum of the series A.P.: 3 + 8 + 13 + 18 + 23 + 28 + 33 = 126
BUILD SUCCESSFUL (total time: 17 seconds)

#### 1 comment:

1. public class JavaApplication1 {

public static void main(String[] args) {
int n1,n2,i,gap;
Scanner sc=new Scanner(System.in);
n1=sc.nextInt();
n2=sc.nextInt();
int sum=0;
gap=sc.nextInt();
int temp=n1;
System.out.print(temp);
for(i=temp;i<=n2+1;i++)
{
n1=n1+gap;
sum+=n1;
System.out.print("+"+n1);
}
System.out.println(sum+temp);
}

}